<![CDATA[What Kimberling point is this? Any chance it is the new one?]]>
https://help.geogebra.org/topic/what-kimberling-point-is-this-any-chance-it-is-the-new-one
Sat, 04 Jul 2020 14:19:03 +0000Sat, 04 Jul 2020 08:04:05 +0000Zend_Feed<![CDATA[Your construction has 2 Kimberling points. x(1)x(1127) This is determined with the four (red) list objects l1,l2,l3,l4. l1 contains the list of the points to be examined (for the triangle A,C,B). The points are examined up to Kimberling number 3053. ------------------------------------------------------ Principle: All Kimberling points up to Kimberling-number 3053 are calculated for the triangle ACB and for those calculated points occurring in l1 the Kimberling number is stored in l2. l3 calculates the Kimberling point for all numbers in l2 l4 creates a text for each point in l3 -------------------------------------------------------- Note: I don't know if the direction of rotation is relevant for the command TriangleCenter(). I used counterclockwise (i.e. triangle ACB)]]>
https://help.geogebra.org/topic/what-kimberling-point-is-this-any-chance-it-is-the-new-one#comment-285448
Sat, 04 Jul 2020 12:52:49 +0000<![CDATA[Thank you. nice to see! I also found that it is possible to construct a point related to the circumcenter D in the similar manner. If E,F,G are the circumcenters of the triangles ABD, BDC, ADC, continuations of the sides of the triangles ABC and EFG meet in 3 points J,H,I that apparently always lie on a common line. In such case (according to the converse to Desargues' theorem) lines BG, AF, CE always intersect at point K. And apparently the same construction can be applied to the 9-point center of ABC as well. Sadly my notebook battery discharged and I lost the .ggb files for these two constructions.]]>
https://help.geogebra.org/topic/what-kimberling-point-is-this-any-chance-it-is-the-new-one#comment-285452
Sat, 04 Jul 2020 14:14:13 +0000<![CDATA[and that brings me to the hypothesis that perhaps the points X(1127) and also X(??), X(???) (both defined in my previous comment) + the original vertices of the triangle ABC can be connected by lines that meet at some other known point X(?)]]>
https://help.geogebra.org/topic/what-kimberling-point-is-this-any-chance-it-is-the-new-one#comment-285454
Sat, 04 Jul 2020 14:20:03 +0000