Properties
Category
English
Similar Topics
Statistics
Comments
3
Participants
2
Subscribers
0
Votes
1
Views
1023
Share
Solved
Hello
Script to reproduce the problem
- -3< (2*x+5)/3 <= 5 -> (2/3*x+5/3)>-3 ∧ 5≥(2/3*x+5/3) // ok
- (2/3*x+5/3)>-3∧5≥(2/3*x+5/3) -> (2/3*x+5/3)>-3∧5≥(2/3*x+5/3) // ok
- Solve[$1] -> { -7 < x ≤ 5 } // ok
- $1 -> (2/3*x+5/3)>-3∧5≥(2/3*x+5/3) // ok
- now one click on output 4 ->error: please check your input ...
- GeoGebra
- Help
- Partners
-
Contact us
- Feedback & Questions
- This email address is being protected from spambots. You need JavaScript enabled to view it.
- +43 677 6137 2693
© 2023 International GeoGebra Institute
The problem happens in version 6, some spaces replace them with multiplications
(2/3*x+5/3)>-3 ∧ 5≥(2/3*x+5/3) ->
(2/3*x+5/3)>-3 ∧ 5*≥*(2/3*x+5/3)
Thanks, we'll check!
Please try the new version (367)
Comments have been locked on this page!