Properties
Similar Topics
Statistics
Comments
11
Participants
3
Subscribers
3
Votes
1
Views
718
Share
Calculate points on sphere?
Answered
In this workbook:
https://www.geogebra.org/m/uydjqdh3
Could someone please tell me how to calculate the coordinates of the intersection points of the latitude and longitude curves with the outermost circumcircle? I do not know the formulas.
Thank you!
Mike
 GeoGebra
 Help
 Partners

Contact us
 Feedback & Questions
 This email address is being protected from spambots. You need JavaScript enabled to view it.
 +43 677 6137 2693
© 2023 International GeoGebra Institute
I don't understand? They are plotted cartesian 2D points not polar or 3D points.
I mean the actual plotted points, not the figure being represented.
I have attached a better example maybe.
For example if:
How do I determine theta? (Two possible answers.)
I don't know how to type that into GeoGebra. When I type it I get:
Where h and a are checkboxes that evaluate to true. (Are you looking at my second example/attachment?)Never mind. The CAS interface works differently.
But the solutions I am getting don't make sense. Do I need to convert the solution to degrees or is it automatic?
The result by default is in radians, so I had to take that into account later on.
The problem now is that the CAS command creates a list, but if I try to access an item in that list I get an "Illegal Argument" error. (See attachment.) The list itself does render the result as points if made visible.
I am looking for an alternative that does not live inside CAS view.
I plotted the function
Then I created the intersection points of this function and the x axis. Unfortunately, these points shift right or left along the function over time as I rotate the sphere using the sliders. Sometimes they are a large distance away. Sometimes they occupy the same location. I need them to stay somewhat in the same place relative to the function and to each other.
Can I set min and max extents of the function?
Comments have been locked on this page!