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Category
French
Due On
2018-07-23
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I think that M_1 = Solutions({f'(x) - g'(y) , f(x) - g(y) - (x - y) f'(x) }) does not work
try to open the tool and redefining M_1 = Solutions({f'(x) - g'(y) = 0, f(x) - g(y) - (x - y) f'(x) = 0}), for M_2 too
Bonjour, à quoi sert M_2 ?( dans quel cas ne serait-ce pas symétrique à M_1 )
Je ne me suis préoccupé que de M_1
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