Not a Problem
Intersection with a list of conics (hyperbolas in my case) only shows 1 intersection point:
1) hyp:x^2-y^2=1 /* hyperbola */
2) x_s:0.5*x /* line */
3) Intersect(x_s, hyp) /* provides 2 intersection points - fine!*/
4) hypList:Sequence(x^2-y^2=n^2, n, 2, 3)
5) Sequence(Intersect(x_s, Element(hypList, k)),k,1,2)
Only shows 1 intersection point - as you can see in the attached file!
The only ugly work around I know is another Sequence with indexed intersection points and flatten the list afterwards.
Why is an element of a list of hyperbolas treated not the same way as a single hyperbola?
Files:
IntersectBug.ggb
The same problem 
Does this help?
5) Sequence({Intersect(x_s, Element(hypList, k))},k,1,2)(maybe with Flatten() too)
Place Intersect() inside this Sequence() in curly brackets -> {Intersect()}
l1 = Flatten(Sequence({Intersect(x_s, Element(hypList, k))}, k, 1, 2))
2 elements must be created per index k. This requires the curly brackets, so that only 1 expression (a list) is created inside the Sequence(). This is then dissolved using Flatten().
---------------
Sorry, time overlap with Michael Borcherds.
Curly brackets are the solution - no chance to see this without your help!
Thank you Michael, thank you rami
Problem solved!
Comments have been locked on this page!