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Not a Problem
In the properties,advanced I use a set of consecutive variations such as 4≥a≥1∨9≥a≥6∨15≥a≥11 ...... which are many and were implemented and when I replaced them with the command Sequence(4 + 5i ≥ a ≥ 1 + 5i, i, 0, 20)Not implemented, please help. Thank you
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Sequence(4 + 5i ≥ a ≥ 1 + 5i, i, 0, 20) is a set with 21 true,false values
if you want OR do sum(Sequence(4 + 5i ≥ a ≥ 1 + 5i, i, 0, 20)) if you want AND do product(Sequence(4 + 5i ≥ a ≥ 1 + 5i, i, 0, 20))
some question?
better to use mod() ie: for c_4 put Mod(a, 5) >= 3
ie: for c_10 put mod(a,50)>=30 or similar
for c_7 Mod(a, 10) ≥ 5
I though your goal was to do .OR.(list of boolean) because you wrote 4≥a≥1∨9≥a≥6∨15≥a≥11 ......
Another principle.
Everything is handled in lists.
In case of doubt: ask.
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