How to find the maximum and minimum y value given the locus graph of a Differential Equation?

I don't understand. Is this the command?

l1 = First(Element({NSolveODE({f', g', h'}, 0, {1, 2, -2}, 3)}, 1), Length(Element({NSolveODE({f', g', h'}, 0, {1, 2, -2}, 3)}, 1)))

Thank you mathmagic.

How to create a point list of each locus graph of a Differential Equation?l1=First(Element({numericalIntegral1},1),Length(Element({numericalIntegral1},1)))

l2=First(Element({numericalIntegral1},2),Length(Element({numericalIntegral1},2)))

l3=First(Element({numericalIntegral1},3),Length(Element({numericalIntegral1},3)))

How to find the maximum and minimum y value given the locus graph of a Differential Equation?

Maxl1=Max(Sequence(y(Element(l1, i)),i,1,Length(l1),1))

Maxl2=Max(Sequence(y(Element(l2, i)),i,1,Length(l2),1))

Minl3=Min(Sequence(y(Element(l3, i)),i,1,Length(l3),1))

Thank you for shortcut command.

This is link the activity:

https://www.geogebra.org/m/fvq7txsw

absolute minimum

ymin=Min({y(Element(Sort(l1, y(l1)), 1)), y(Element(Sort(l2, y(l2)), 1)), y(Element(Sort(l3, y(l3)), 1))})

absolute maximum

ymax=Max({y(Element(Sort(l1, y(l1)), Length(l1))), y(Element(Sort(l2, y(l2)), Length(l2))), y(Element(Sort(l3, y(l3)), Length(l3)))})

absolute minimum

ymin=Min({y(Element(Sort(l1, y(l1)), 1)), y(Element(Sort(l2, y(l2)), 1))})

absolute maximum

ymax=Max({y(Element(Sort(l1, y(l1)), Length(l1))), y(Element(Sort(l2, y(l2)), Length(l2)))})

minimum

ymin=y(Element(Sort(l1, y(l1)), 1))

maximum

ymax=y(Element(Sort(l1, y(l1)), Length(l1)))