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2020-04-07
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I was given a problem involving the function f(x) =sqrt(2x^2-y).
I was asked to find the direction of maximum increase and the maximum increase (and the same for the direction of minimum increase and minimum increase) for f(3,2).
I found the numbers, but I can't figure out how to graph them so that I can picture it. Any ideas?
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this?
the up attached has an error
la explicacion está en cualquier libro o apunte sobre el gradiente de una función
puedo explicar los pasos en español pero en resumen las derivadas parciales dan la dirección de máxima pendiente y su modulo es la máxima pendiente así pues el vector es (f_x , f_y , |(f_x,f_y)|) es el vector que deseo graficar desde el punto B; esto se puede hacer con el comando vector()
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