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Gibert Point unique?
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I'm constructing this point (x24) using a random triangle...
There are many way to achieve this...four that I know.
So in using the same triangle with different methods of construction the point is in a different position in every case...
Any help, or is x24 not unique to any triangle?
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your L' is not correct
you do L'=L reflected in P but L' must be P reflected in b_1
and so on
Prasolov Point in the sides of the Excentral Triangle.
saludos
x(24) is unique. perhaps your methods get another points defined by Gibert. there are many Gibert's works about centers of triangles.
can you share your methods?
http://www.ddekov.eu/j/2007...
I'm working on the five example in the document...and using the same triangle...but the point seems to be in different places...
can you share the worksheet and the text of fifth example?. there is not numbers in the examples
"hay tres clases de matemáticos: los que saben contar y los que no"
saludos
I'm good with all the examples in the document now...except the example on page 3, constructing the Gibert Point using the Prasolov point reflections...
Can you help please...
https://www.geogebra.org/m/R25GbcnP
Thank you for this its a great help...
But I'm trying to reproduce the diagram on page three and I can't, I think the illustration is wrong...
I'll try again to understand...its back to the same issue the Gibert point appears in a different place...
Many thanks
I inserted the diagram in my worksheet and after translation of A,B,C was coincident in all its elements
perhaps you builded other external triangle
Reworked but still cannot get the blue lines to meet at the Gibert point...
your L' is not correct
you do L'=L reflected in P but L' must be P reflected in b_1
and so on
Prasolov Point in the sides of the Excentral Triangle.
saludos
Thank you, thank you, thank you.....
I have it now...
Thank you for sharing your talent with me...
Clive
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