# Gibert Point unique?

academic shared this question 5 years ago

I'm constructing this point (x24) using a random triangle...

There are many way to achieve this...four that I know.

So in using the same triangle with different methods of construction the point is in a different position in every case...

Any help, or is x24 not unique to any triangle?

you do L'=L reflected in P but L' must be P reflected in b_1

and so on

1. Gibert Point = Perspector of Triangle ABC and the Triangle of the reflections of the

Prasolov Point in the sides of the Excentral Triangle.

saludos

1

x(24) is unique. perhaps your methods get another points defined by Gibert. there are many Gibert's works about centers of triangles.

1

I'm working on the five example in the document...and using the same triangle...but the point seems to be in different places...

1

can you share the worksheet and the text of fifth example?. there is not numbers in the examples

"hay tres clases de matemáticos: los que saben contar y los que no"

saludos

1

I'm good with all the examples in the document now...except the example on page 3, constructing the Gibert Point using the Prasolov point reflections...

1
1

Thank you for this its a great help...

But I'm trying to reproduce the diagram on page three and I can't, I think the illustration is wrong...

I'll try again to understand...its back to the same issue the Gibert point appears in a different place...

Many thanks

1

I inserted the diagram in my worksheet and after translation of A,B,C was coincident in all its elements

perhaps you builded other external triangle

1

Re-worked but still cannot get the blue lines to meet at the Gibert point...

2

you do L'=L reflected in P but L' must be P reflected in b_1

and so on

1. Gibert Point = Perspector of Triangle ABC and the Triangle of the reflections of the

Prasolov Point in the sides of the Excentral Triangle.

saludos

1

Thank you, thank you, thank you.....

I have it now...

Thank you for sharing your talent with me...

Clive