Get current zooming factor

Hi,

https://wiki.geogebra.org/en/ZoomIn_Command

https://wiki.geogebra.org/en/ZoomOut_Command

"Current zooming factor" does not exist.

However you may want to read

https://wiki.geogebra.org/en/Corner_Command

You can calculate based on the coordinate system you have set up, what are the coordinates of the extent of your specific graphics window view.

May I leave you to read https://wiki.geogebra.org/en/Corner_Command

and see example at https://www.geogebra.org/cl...

Regards,

lewws

zoomin is undependent for each axes so the general answer is not possible

if you want the zoom for xAxis you can do (x(Corner(5)) + 2) / 50 / x(Corner(3) - Corner(1))

The goal is to calculate the distance of 2 points in (pixels if the x/y ratio not is 1/1)

This is possible with the formula in the attachment (I think)

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But:

There is another question still unresolved for me:

How to draw a perpendicular to a path if the X/Y-ratio is not 1/1. The perpendicular should appear in 90° on the screen (that mean the angle look on the screen alway same, also when the X/Y-ratio is changed).

This is the prerequisite for determining the closestPointOnPath on the screen (not calculatet in GGB-units by GGB) between a path and a point when the X/Y ratio is not 1/1.

espero que el adjunto se explique solo, aunque esté calculado en español

Thank you very much mathmagic,

.

I think instead of Spanish, I'm going to learn the matrix calculus.

So I would be able to really appreciate your work.

And, maybe, then I might be able to create what I really want by myself.

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Finally, I wanna:

I have a path c and a point P

I want the C=ClosestPoint(c,p) so that if the ratio XY is not 1:1, the picture on the screen looks like it is 1:1. So that Distance(C,D) in pixels (viewed on the screen) is the smallest possible value.

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story until now:

I wanted to reach this step by step. First with point and straight line.

I even achieved this (method TrailAndError). Only, unfortunately I don't understand why it works (if it does).

In the attachment my "solution" only to clarify what I am looking for.

And logically, with this not knowing, I do not reach the final goal (ClosestPointInPixel).

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I hope to formulate understandingly what I am looking for.

I would be pleased if you could support me in this task (of course with the "magic Spanish matrix", if possible).

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Note: I use deepL (mark a text anywhere (even inside GGB) and then double ctr-C-C) the translation is better than that of google.

Thanks for ongoing discussion here.

Learning ideas and techniques from you both.

Thank you so much!

un intento poco testado

Thanks a lot mathmagic.

It works great.

I will still analyze your solution and try to understand the principle.

I intend to implement this code in this program (will take some time)

.

Best regards and thanks again

Raymond

he estado testando y creo que es necesario cambiar la definicion del punto B definiendo B=corner(5)+(2,2)

así, cuando la ventana grafica está en standar view la matriz GP vale {{50,0},{0,-50}} que creo es lo correcto

trying setaxesratio(100,1)

I got strange numbers in matrix

I was thinking about this in the first work but I though it was rounding problem. 100:1 shows it is not a rounding problem