Functions defined on a limited interval and solve equation

OLDen shared this question 7 months ago
Answered

Hi

Is there difference between using the commands

- Function(f(x),start,end)

- If(start<=x<=end,f(x))

?

When I want to use the command solve then I can't use function defined on limited interval.

I then have to solve the equation graphically.

Is there an explaination for this issue?

Regards

Olav

Comments (2)

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1

Solve({f(x)=0,start<=x,x<=end}) for example: Solve({(x-1)(x-3)=0,0<=x,x<=2})

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1

look at the syntax of solve().


https://wiki.geogebra.org/e...

try Roots( <Function>, <Start x-Value>, <End x-Value> )

eg: roots((x-1)(x-3)=0,0,2)

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