Fourier transformation: why complex integral-results

sabaot.f shared this question 3 years ago
Answered

Hello!

For School, I just wanted to make a fouriertransformation. I just wonder why I get ί in the results. There can't be something complex, does it?


  1. \mathbf{b(n) \, := \, \frac{-6 \; ί \; \operatorname{sin} \left( n \; \pi \right) - 6 \; \operatorname{cos} \left( n \; \pi \right)}{n \; \pi}}

Does someone know, why this happens? (the ί)

It seems that this leads to not be able to view this plot ...

I'm using GeoGebra 5.0.311.0-3D on LM 18.


Thanks in advance!

Thomas

Comments (2)

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Hi Thomas,


I don't understand exactly what you need. Do you want b(n) to be displayed as a number?


Anyway, I made this worksheet hoping it is useful. See file attached and check the script in the Setup button.


Cheers!

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I meant: Do you want b(n) to be displayed as a real number?

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