Divide a segments into even lengths

tush shared this question 3 years ago

Answered

Let

f1=Segment ( Point( {0,0} ) , Point( {1,0} ) )

One can draw N equally spaced points along this segment in the following way:

list1 = Sequence ( Point( f , k ) , k , 0 , 1 , n)

where N=1/n an integer number.

I want to create another list of points along this "curve", using the `Sequence` command, to contain the points just in between those in list1.

For example, if list1 contains the set of points

[ 0 , 0.1 , 0.2 , 0.3 , ... 0.9 , 1 ]

I want list2 to be the list of points

[ 0.05, 0.15 , 0.25 , 0.35 , 0.45 , ... , 0.95 ]

Important: I want to use as the input argument to the `Sequence` command the `Point( <Object>, <Parameter> )` tool, in a similar way to that I used to define list1.

I tried a multiple of variations on the increment argument in the sequence command, and on the parameter in Point( object, parameter ) but nothing worked, so I am uploading this question.

Thanks a lot for your help.

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Comments (2)

Noel Lambert ● 3 years ago

Sequence(Point(f1, (5 + k) / 100), k, 0, 90, 10)

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tush ● 3 years ago

Brilliant. Thanks very much.

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