Divide a perimeter to equal lenth

Idan Tal shared this question 6 years ago
Answered

Hi,


I have a quadrangle (not a square) which its length is 10.

I want to divide its perimeter by 5 point to 5 polylines of lentgh 2.


Is there any simple way to do it by geogebra?


Thanks,


Idan

Comments (12)

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I don't understand Noel what you say. Can you explain please?

photo
1

Here is an example of my problem.


Here you can see a square and a hexagon (which look likes a square).

I'm trying to make the slider works the same in these 2 polygons.

Files: ttt.ggb
photo
1

Let's try something more easy.

I have a quadrangle (not a square) which its length is 10 and a point A on it's perimeter.

I want that point B will move on the same perimeter with length 2 between A and B.

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2

hello


  1. Let's try something more easy.

    I have a quadrangle (not a square) which its length is 10 and a point A on it's perimeter.

    I want that point B will move on the same perimeter with length 2 between A and B.

the names need reordenation but I am hungry

saludos

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Here is something I made on a square divided to 5 (the length between any 2 point on the perimeter is 4).


https://www.geogebra.org/m/y9S8Pzcw


I'm tring to do the same thing on another quadrangle and I can't.

Can someone help me?

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why my work is not enough?

photo
1

Oh, I'm sorry, I didn't see your wonderful attached file.


Thank you very very mach mathmagic :-)

It works great!!!

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Same principle as mathmagic (4 hours later)

All with PathParameter and more Lists

Note:

Ppp mean PolyPathParameter, Spp mean SinglePathParameter or SegmentPathParameter

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Thank you Rami!!!

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Today, after eating and sleeping, I have more time for another step in the topic

open the link and use the tool with poly1,n,param

https://www.geogebra.org/m/yrxnwJ9k

saludos

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extending the discussion on pathparameter i need help how to set my initial point at "Noon " instead of at the default point 'M'. ( ie need find the distance travelled by C starting from point 'Noon' . ). any help is very much appreciated . thanks

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Awesome!

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