 GeoGebra
 Help
 Partners

Contact us
 Feedback & Questions
 This email address is being protected from spambots. You need JavaScript enabled to view it.
 +43 677 6137 2693
© 2019 International GeoGebra Institute
Defining the curves in your definition separately as functions, you can see that indeed there's no intersection.
In this case I think working with functions is easier than using curves: f(x)=Function[cos(x), 0, pi]
chris
hello
there is a bug
saludos
does numeric search so can't always find the intersection
Try
yes, it works
but the help of intersect says
Intersect[ <Curve 1>, <Curve 2>, <Parameter 1>, <Parameter 2> ]Finds one intersection point using a numerical, iterative method starting at the given parameters.
Example:
Let a = Curve[cos(t), sin(t), t, 0, π] and b = Curve[cos(t) + 1, sin(t), t, 0, π].
Intersect[a, b, 0, 2] yields the intersection point A = (0.5, 0.87).
saludos
... but in this case it is actually a bug. Fixed for next release (5.0.333.0)
Comments have been locked on this page!