Answered
Is completing the square possible when the equation has both x and y? For example
x^2 + y^2 - 3x + y -1/4 would be (x - 3/2)^2 + (y + 1/2)^2 - 9/4, but can you do that with Geogebra?
The same question 
Is completing the square possible when the equation has both x and y? For example
x^2 + y^2 - 3x + y -1/4 would be (x - 3/2)^2 + (y + 1/2)^2 - 9/4, but can you do that with Geogebra?
Yup, enter
It is true that there is no command to transform the polygon :
P(x)= x² + y² - 3x + y - 1 / 4 = 0
into
Q(x) = (x - 3 / 2)² + (y + 1 / 2)² - 11 / 4 = 0
You can build an user fonction (a tool) using commands :
Center(c) and radius(c) :
to display the expression you like.
(x-x(center(c))+(y-y(center(c))=radius(c)^2.
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