CAS Definition handling 6.x

hawe shared this problem 5 months ago
Not a Problem

Definition not availavle in CAS

https://www.geogebra.org/m/rzbtquc8


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Comments (1)

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1

It is a mismatch by subscription handling....

input <===> Definition

Q_K <===> Q_K

Q_k <===> Q_{k}

CAS input Q_K makes Q_{K} in formula

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