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Area under the curve in 3D
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Hello
I got the red curve (in the picture) by rotating f(x)=x^2 by 90° across xaxis, and then the new one by 90° across zaxis. There is probably more elegant way to do this, but what I really need is this surface under the curve and above xy plane
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area_under_the_...
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it seems your area is equal to area under y=x^2 above y axis in R2 so area=integral(x^2,2,2)=16/3
What I need is to plot the surface.
surface(0,t,u*t^2,t,2,2,u,0,1)
Thank you very much!
On a side note, do you have some good GeoGebra 3d tutorials/courses to recommend?
sorry
there is a link to official tutorials here https://www.geogebra.org/a/14 but I do not know them
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