Area under the curve in 3D

Matea Pjanic shared this question 2 years ago
Answered

Hello

I got the red curve (in the picture) by rotating f(x)=x^2 by 90° across x-axis, and then the new one by 90° across z-axis. There is probably more elegant way to do this, but what I really need is this surface under the curve and above xy plane

Comments (5)

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it seems your area is equal to area under y=x^2 above y axis in R2 so area=integral(x^2,-2,2)=16/3

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What I need is to plot the surface.

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surface(0,t,u*t^2,t,-2,2,u,0,1)

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Thank you very much!

On a side note, do you have some good GeoGebra 3d tutorials/courses to recommend?

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sorry


there is a link to official tutorials here https://www.geogebra.org/a/14 but I do not know them

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